How to convert integer number into binary vector?
How to convert an integer number into binary vector using R?
For example :
number <- 11
[1] 1 0 1 1
what is the fastest possible method of conversion (using R code or some existing functions from packages) if I need to convert whole vector of numbers (minimum value = 0, maximum =300) into binary matrix ?
Follow the rabbit :
base::intToBits
There's the intToBits
function that converts any integer to a vector of 32 raws, so you can do this:
decimals <- c(3,5,11,4)
m <- sapply(decimals,function(x){ as.integer(intToBits(x))})
m
> m
[,1] [,2] [,3] [,4]
[1,] 1 1 1 0
[2,] 1 0 1 0
[3,] 0 1 0 1
[4,] 0 0 1 0
[5,] 0 0 0 0
[6,] 0 0 0 0
[7,] 0 0 0 0
[8,] 0 0 0 0
[9,] 0 0 0 0
[10,] 0 0 0 0
[11,] 0 0 0 0
[12,] 0 0 0 0
[13,] 0 0 0 0
[14,] 0 0 0 0
[15,] 0 0 0 0
[16,] 0 0 0 0
[17,] 0 0 0 0
[18,] 0 0 0 0
[19,] 0 0 0 0
[20,] 0 0 0 0
[21,] 0 0 0 0
[22,] 0 0 0 0
[23,] 0 0 0 0
[24,] 0 0 0 0
[25,] 0 0 0 0
[26,] 0 0 0 0
[27,] 0 0 0 0
[28,] 0 0 0 0
[29,] 0 0 0 0
[30,] 0 0 0 0
[31,] 0 0 0 0
[32,] 0 0 0 0
This SO post suggests the intToBits
function. I define the function number2binary
, which includes an argument noBits
to control how many bits are returned. Standard is to return 32 bits.
number2binary = function(number, noBits) {
binary_vector = rev(as.numeric(intToBits(number)))
if(missing(noBits)) {
return(binary_vector)
} else {
binary_vector[-(1:(length(binary_vector) - noBits))]
}
}
And for some examples:
> number2binary(11)
[1] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 1
> number2binary(11, 4)
[1] 1 0 1 1
Try the CRAN package "binaryLogic"
library(binaryLogic)
as.binary(11)
[1] 1 0 1 1
as.binary(11, littleEndian=TRUE)
[1] 1 1 0 1
as.binary(42, n=16)
[1] 0 0 0 0 0 0 0 0 0 0 1 0 1 0 1 0
as.binary(0:2, n=2)
[[1]]
[1] 0 0
[[2]]
[1] 0 1
[[3]]
[1] 1 0
as.binary(0xFF)
[1] 1 1 1 1 1 1 1 1
Also available: shift, rotate, graycode etc.